If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6z^2+11z+3=0.
a = 6; b = 11; c = +3;
Δ = b2-4ac
Δ = 112-4·6·3
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-7}{2*6}=\frac{-18}{12} =-1+1/2 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+7}{2*6}=\frac{-4}{12} =-1/3 $
| 13=19-5y | | 1x+28=x | | 3x+6=2x+56 | | 12/120=6/x | | -7n=2n=3n-7n+8 | | 0=0.2x-x | | 8-2(x-10)=5x | | 42-6x=2x+50 | | 3(4x-10)-8x=2 | | 8x+6=3x+15 | | 2(x+1)=1(2+2x) | | x=(11+33−42)÷(8−4) | | (11+33−42)÷(8−4)=x | | 6x+19-4x=39 | | 1/2x+3/4=4x+3/2 | | 22(x+4)=8+2x | | X-9/2=x+1/3 | | 4x+1/5=5x+2/5 | | x-7=3-9 | | –6+4v=10v | | 3/4a-1/2=1/2a-5/6 | | 10x-20+7x+30=180 | | 2(x1/)/4=4x-3 | | –3d+10=–d | | 12x-6+20x=90 | | 9x+7=14x+17 | | 15y+21=81 | | 6x+17+10x+10=155 | | t^2-10t+16=4-2t | | |x-9|+2=16 | | X=18y= | | 8x+11-2x=41 |